Integrand size = 21, antiderivative size = 215 \[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=-\frac {2}{27 a c \left (c+a^2 c x^2\right )^{3/2}}-\frac {40}{9 a c^2 \sqrt {c+a^2 c x^2}}-\frac {2 x \arctan (a x)}{9 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {40 x \arctan (a x)}{9 c^2 \sqrt {c+a^2 c x^2}}+\frac {\arctan (a x)^2}{3 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 \arctan (a x)^2}{a c^2 \sqrt {c+a^2 c x^2}}+\frac {x \arctan (a x)^3}{3 c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 x \arctan (a x)^3}{3 c^2 \sqrt {c+a^2 c x^2}} \]
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Time = 0.13 (sec) , antiderivative size = 215, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {5020, 5018, 5014, 5016} \[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\frac {2 x \arctan (a x)^3}{3 c^2 \sqrt {a^2 c x^2+c}}+\frac {2 \arctan (a x)^2}{a c^2 \sqrt {a^2 c x^2+c}}-\frac {40 x \arctan (a x)}{9 c^2 \sqrt {a^2 c x^2+c}}+\frac {x \arctan (a x)^3}{3 c \left (a^2 c x^2+c\right )^{3/2}}+\frac {\arctan (a x)^2}{3 a c \left (a^2 c x^2+c\right )^{3/2}}-\frac {2 x \arctan (a x)}{9 c \left (a^2 c x^2+c\right )^{3/2}}-\frac {40}{9 a c^2 \sqrt {a^2 c x^2+c}}-\frac {2}{27 a c \left (a^2 c x^2+c\right )^{3/2}} \]
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Rule 5014
Rule 5016
Rule 5018
Rule 5020
Rubi steps \begin{align*} \text {integral}& = \frac {\arctan (a x)^2}{3 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {x \arctan (a x)^3}{3 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {2}{3} \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^{5/2}} \, dx+\frac {2 \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{3 c} \\ & = -\frac {2}{27 a c \left (c+a^2 c x^2\right )^{3/2}}-\frac {2 x \arctan (a x)}{9 c \left (c+a^2 c x^2\right )^{3/2}}+\frac {\arctan (a x)^2}{3 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 \arctan (a x)^2}{a c^2 \sqrt {c+a^2 c x^2}}+\frac {x \arctan (a x)^3}{3 c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 x \arctan (a x)^3}{3 c^2 \sqrt {c+a^2 c x^2}}-\frac {4 \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{9 c}-\frac {4 \int \frac {\arctan (a x)}{\left (c+a^2 c x^2\right )^{3/2}} \, dx}{c} \\ & = -\frac {2}{27 a c \left (c+a^2 c x^2\right )^{3/2}}-\frac {40}{9 a c^2 \sqrt {c+a^2 c x^2}}-\frac {2 x \arctan (a x)}{9 c \left (c+a^2 c x^2\right )^{3/2}}-\frac {40 x \arctan (a x)}{9 c^2 \sqrt {c+a^2 c x^2}}+\frac {\arctan (a x)^2}{3 a c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 \arctan (a x)^2}{a c^2 \sqrt {c+a^2 c x^2}}+\frac {x \arctan (a x)^3}{3 c \left (c+a^2 c x^2\right )^{3/2}}+\frac {2 x \arctan (a x)^3}{3 c^2 \sqrt {c+a^2 c x^2}} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.48 \[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\frac {\sqrt {c+a^2 c x^2} \left (-2 \left (61+60 a^2 x^2\right )-6 a x \left (21+20 a^2 x^2\right ) \arctan (a x)+9 \left (7+6 a^2 x^2\right ) \arctan (a x)^2+9 a x \left (3+2 a^2 x^2\right ) \arctan (a x)^3\right )}{27 a c^3 \left (1+a^2 x^2\right )^2} \]
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Result contains complex when optimal does not.
Time = 4.17 (sec) , antiderivative size = 308, normalized size of antiderivative = 1.43
method | result | size |
default | \(-\frac {\left (9 i \arctan \left (a x \right )^{2}+9 \arctan \left (a x \right )^{3}-2 i-6 \arctan \left (a x \right )\right ) \left (a^{3} x^{3}-3 i a^{2} x^{2}-3 a x +i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{216 \left (a^{2} x^{2}+1\right )^{2} c^{3} a}+\frac {3 \left (\arctan \left (a x \right )^{3}-6 \arctan \left (a x \right )+3 i \arctan \left (a x \right )^{2}-6 i\right ) \left (a x -i\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}}{8 a \,c^{3} \left (a^{2} x^{2}+1\right )}+\frac {3 \sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (a x +i\right ) \left (\arctan \left (a x \right )^{3}-6 \arctan \left (a x \right )-3 i \arctan \left (a x \right )^{2}+6 i\right )}{8 a \,c^{3} \left (a^{2} x^{2}+1\right )}-\frac {\left (-9 i \arctan \left (a x \right )^{2}+9 \arctan \left (a x \right )^{3}+2 i-6 \arctan \left (a x \right )\right ) \sqrt {c \left (a x -i\right ) \left (a x +i\right )}\, \left (a^{3} x^{3}+3 i a^{2} x^{2}-3 a x -i\right )}{216 \left (a^{4} x^{4}+2 a^{2} x^{2}+1\right ) c^{3} a}\) | \(308\) |
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none
Time = 0.25 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.52 \[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=-\frac {\sqrt {a^{2} c x^{2} + c} {\left (120 \, a^{2} x^{2} - 9 \, {\left (2 \, a^{3} x^{3} + 3 \, a x\right )} \arctan \left (a x\right )^{3} - 9 \, {\left (6 \, a^{2} x^{2} + 7\right )} \arctan \left (a x\right )^{2} + 6 \, {\left (20 \, a^{3} x^{3} + 21 \, a x\right )} \arctan \left (a x\right ) + 122\right )}}{27 \, {\left (a^{5} c^{3} x^{4} + 2 \, a^{3} c^{3} x^{2} + a c^{3}\right )}} \]
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\[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int \frac {\operatorname {atan}^{3}{\left (a x \right )}}{\left (c \left (a^{2} x^{2} + 1\right )\right )^{\frac {5}{2}}}\, dx \]
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\[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int { \frac {\arctan \left (a x\right )^{3}}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \]
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\[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int { \frac {\arctan \left (a x\right )^{3}}{{\left (a^{2} c x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\arctan (a x)^3}{\left (c+a^2 c x^2\right )^{5/2}} \, dx=\int \frac {{\mathrm {atan}\left (a\,x\right )}^3}{{\left (c\,a^2\,x^2+c\right )}^{5/2}} \,d x \]
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